Limitler Toplamı

${\displaystyle \underset{x\to -\infty }{lim}\left(7^{\frac{1}{x}}\right)+5^x+1=?}$

Çözüm:

${\displaystyle \underset{x\to -\infty }{lim}\left(7^{\frac{1}{x}}\right)+5^x+1=\underset{x\to -\infty }{lim}\left(7^{\frac{1}{x}}\right)+\underset{x\to -\infty }{lim}{5}^x+\underset{x\to -\infty }{lim}1}$

${\displaystyle =\underset{x\to -\infty }{lim}\left(7^{\frac{1}{x}}\right)+\underset{x\to +\infty }{lim}{\left(\frac{1}{5}\right)}^x+\underset{x\to -\infty }{lim}1}$

${\displaystyle =1+0+1}$

${\displaystyle =2}$

( 1993 - Ö S S )